Does every Schema.org property have a Google rich result feature?

Definition: No. Schema.org is a shared vocabulary of types and properties, while Google documents the properties that have special meaning for a particular Search feature. A property can describe a page in Schema.org without appearing in a Google rich result guide.

Key facts

• Google's structured data introduction says structured data is a standardized format for providing information about a page and classifying its content.
• Schema.org describes shared vocabularies and supports the Microdata, RDFa, and JSON-LD formats. Its documentation covers types, properties, and inheritance across the vocabulary. Schema.org's getting started guide gives these examples.
• Google says most Search structured data uses the Schema.org vocabulary, but Google Search Central documentation is definitive for Google Search behavior rather than Schema.org documentation.
• Google also says that Schema.org contains attributes and objects that Google Search does not require. They may still be useful to other search engines, services, tools, and platforms.
• Google’s structured data feature gallery groups the supported Search appearances into feature guides, such as Article, Breadcrumb, Product, Recipe, and Video.

What does Schema.org define?

Schema.org provides a collection of shared vocabularies that webmasters can use to mark up pages for interpretation by major search engines. The vocabulary is used with Microdata, RDFa, or JSON-LD, so the vocabulary and the markup format are separate parts of an implementation.

Its type system is broader than any one Search appearance. Schema.org says that each item type has properties for describing it, and that more specific types inherit properties from broader types. For example, its guide states that LocalBusiness is more specific than Place and inherits properties from its parent types. A property therefore belongs first to a vocabulary model, not automatically to a Google result layout.

What does Google document for Search?

Google’s documentation, updated 10 December 2025, describes which properties are required, recommended, or optional when they have special meaning to Google Search. It says that all required properties must be included for an object to be eligible for an enhanced Search appearance, and that the markup must follow the general and feature-specific guidelines.

Google’s feature gallery is the practical index for this second layer. It describes rich results as richer appearances in Search and sends readers to a guide for each feature. A guide can therefore define a narrower set of properties and conditions than the full Schema.org vocabulary. Google says some other Schema.org structured data can be used generally, and that some elements may support future Search features if Google considers them useful.

How should you choose properties?

Start with the Schema.org type and properties that accurately describe the visible content on the page. Then check the Google guide for the Search feature that matches the page, including its required and recommended properties, feature-specific guidelines, and supported format.

For example, Google’s introduction uses JSON-LD with a Schema.org Recipe type:

{
  "@context": "https://schema.org/",
  "@type": "Recipe",
  "name": "Non-Alcoholic Piña Colada"
}

The presence of a Schema.org property in valid markup is a vocabulary fact. Whether Google assigns that property a role in a particular Search feature is answered by the corresponding Google documentation. If no Google feature guide documents a property, its role in a Google rich result is undocumented in the sources used here.

Related terms

• Structured data
• JSON-LD
• How does Schema.org validation differ from Google's Rich Results Test?
• How do I test a URL or code snippet with Google's Rich Results Test?

FAQ

Does valid Schema.org markup make a page eligible for a Google rich result?

No. Google requires the properties and guidelines documented for the relevant feature, and it evaluates the markup in that feature-specific context.

Are Schema.org properties outside Google’s feature guides useless?

No. Google says that additional Schema.org attributes and objects may be useful for other search engines, services, tools, and platforms. Google can also make general use of sameAs and other Schema.org structured data.

Which documentation should you use for a Google Search implementation?

Use Schema.org to understand the vocabulary and Google Search Central to understand Search behavior, required properties, supported formats, and feature-specific guidelines. Google recommends the Rich Results Test for validation and, in some cases, feature previewing.

Sources

1. Google Search Central, "Introduction to structured data markup in Google Search", 10 December 2025
2. Schema.org, "Getting started with schema.org using Microdata", undated
3. Google Search Central, "Structured data markup that Google Search supports", 16 October 2026

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